-(1-x)-[2x-(3-x)]=8

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Solution for -(1-x)-[2x-(3-x)]=8 equation:


Simplifying
-1(1 + -1x) + -1[2x + -1(3 + -1x)] = 8
(1 * -1 + -1x * -1) + -1[2x + -1(3 + -1x)] = 8
(-1 + 1x) + -1[2x + -1(3 + -1x)] = 8
-1 + 1x + -1[2x + (3 * -1 + -1x * -1)] = 8
-1 + 1x + -1[2x + (-3 + 1x)] = 8

Reorder the terms:
-1 + 1x + -1[-3 + 2x + 1x] = 8

Combine like terms: 2x + 1x = 3x
-1 + 1x + -1[-3 + 3x] = 8
-1 + 1x + [-3 * -1 + 3x * -1] = 8
-1 + 1x + [3 + -3x] = 8

Reorder the terms:
-1 + 3 + 1x + -3x = 8

Combine like terms: -1 + 3 = 2
2 + 1x + -3x = 8

Combine like terms: 1x + -3x = -2x
2 + -2x = 8

Solving
2 + -2x = 8

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-2' to each side of the equation.
2 + -2 + -2x = 8 + -2

Combine like terms: 2 + -2 = 0
0 + -2x = 8 + -2
-2x = 8 + -2

Combine like terms: 8 + -2 = 6
-2x = 6

Divide each side by '-2'.
x = -3

Simplifying
x = -3

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